2^2+4x=-9(3^3-8x)+1

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Solution for 2^2+4x=-9(3^3-8x)+1 equation: 



2^2+4x=-9(3^3-8x)+1

We move all terms to the left:

2^2+4x-(-9(3^3-8x)+1)=0

We add all the numbers together, and all the variables

4x-(-9(3^3-8x)+1)+4=0



We calculate terms in parentheses: -(-9(3^3-8x)+1), so:

-9(3^3-8x)+1

We multiply parentheses

72x-243+1

We add all the numbers together, and all the variables

72x-242

Back to the equation:

-(72x-242)



We get rid of parentheses

4x-72x+242+4=0

We add all the numbers together, and all the variables

-68x+246=0

We move all terms containing x to the left, all other terms to the right

-68x=-246

x=-246/-68

x=3+21/34

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